Question

What is the de Broglie wavelength of (a) a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s, (b) a ball of mass 0.060 kg moving at a speed of 1.0 m/s, and (c) a dust particle of mass 1.0 X 10⁻⁹ kg drifting with a speed of 2.2 m/s?

Answer 1

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Answer 2

De-broglie's wavelength is given as $\lambda=\frac{h}{mv}$

where h is Plank's constant, m is mass of particle and v is speed of that particle.

(a) m = 0.04kg, v = 1km/s = 1000 m/s

so, De-broglie's wavelength, λ = 6.6 × 10^-34/(0.04 × 1000)

= 1.65 × 10^-35 m

(b) m = 0.06kg, v = 1m/s

so, De-broglie's wavelength, λ = h/mv

= 6.6 × 10^-34/(0.06 × 1)

= 1.1 × 10^-32 m

(c) m = 10^-9 kg, v = 2.2 m/s

so, De-broglie's wavelength, λ = h/mv

= 6.6 × 10^-34/(10^-9 × 2.2 )

= 3 × 10^-25 m