Question

What is the decimal form of (0.333…)2?
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Answer 1

Given :      (0.3333...)²

To Find : Decimal form

Solution:

(0.3333...)²   = N²

N =0.3333...

=> N = $0.\overline{3}$

=> 10N = $3.\overline{3}$

=> 9N = 3

=> N = 3/9

=> N = 1/3

=> N² = 1/9

=> N² = 0.1111111..

(0.3333...)²   =  0.11111..

= $0.\overline{1}$

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Answer 2

Answer:

Step-by-step explanation: