Question

what is the decrease in wait of a body mass 500 kg when it is taken into a mine of depth 1000km? (given:R=6400)km

Answer 1

g(d)g(d)=g[1−dR]=g[1−dR],

where gg is acceleration due to gravity, dd is depth of mine and RR is radius of Earth, and g(d)g(d)refers to the value of gg at the depth dd.

Applying the values in the above equation:

gg=9.8[1−10006371000]=9.8[1−10006371000]

=9.7985m/s2=9.7985m/s2.

Hence, difference in weight

=mg−mg(d)=mg−mg(d)

=500(9.8–9.7985)=0.7691=500(9.8–9.7985)=0.7691kg.