Question

What is the decrease in weight of a body of mass 500kg when it is takem into a mine pf depth 1000km?

Answer 1

$\huge\red{solution}$

g(d)g(d)=g[1−dR]=g[1−dR],

where gg is acceleration due to gravity, dd is depth of mine and RR is radius of Earth, and g(d)g(d)refers to the value of gg at the depth dd.

Applying the values in the above equation:

gg=9.8[1−10006371000]=9.8[1−10006371000]

=9.7985m/s2=9.7985m/s2.

Hence, difference in weight

=mg−mg(d)=mg−mg(d)

=500(9.8–9.7985)=0.7691=500(9.8–9.7985)=0.7691kg.