Question

What is the decreasing order of strengths of bonds between $sp^{3}$, $sp^{2}$ and sp hybrid orbitals?

Answer 1

Bond strength and bond length are influenced by hybridization. Especially it completely depends upon the s- orbital.

s- orbitals are closer to the nucleus therefore forms stronger and shorter bonds The length of the bond and the strength of the bond are inversely linked, i.e. the longer the bond is, the weaker the bond strength.

‘s’ and ‘p’ character in different hybridization states is as follows.

Therefore, order of bond strength in different hybridization states is as follows.

$sp\quad >\quad s{ p }^{ 2 }\quad >\quad s{ p }^{ 3 }$

Answer 2

Bond strength and bond length are influenced by hybridization. Especially it completely depends upon the s- orbital.

s- orbitals are closer to the nucleus therefore forms stronger and shorter bonds The length of the bond and the strength of the bond are inversely linked, i.e. the longer the bond is, the weaker the bond strength.

‘s’ and ‘p’ character in different hybridization states is as follows.