Question

What is the degree of deviation, and deviation in light?

Answer 1

Answer:

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When a light ray enters one refracting surface of the prism, it bends towards the normal and when it emerges out of the other refracting surface it bends away from the normal. The angle between the incident ray and the emergent ray is the angle of deviation.

Angle of deviation by reflection (δ) is the angle between extended incident ray & reflected ray.

Angle of deviation is = 2* the glance angle. It is a law that the incident angle is = to the angle of reflection. The perpendicular normal will have an angle of 90 degrees. we know that incident angle is = to the angle of reflection so reflection angle = 30 degrees so the glance angle is 90–30=60 degrees.Angle of deviation is = 2* the glance angle so 2*60 = 120 degrees.Hence delta= 120 degrees.

answer;120 degrees.

Answer 2

Answer:

When a light ray enters one refracting surface of the prism, it bends towards the normal and when it emerges out of the other refracting surface it bends away from the normal. The angle between the incident ray and the emergent ray is the angle of deviation.

Angle of deviation by reflection (δ) is the angle between extended incident ray & reflected ray.

Angle of deviation is = 2* the glance angle. It is a law that the incident angle is = to the angle of reflection. The perpendicular normal will have an angle of 90 degrees. we know that incident angle is = to the angle of reflection so reflection angle = 30 degrees so the glance angle is 90–30=60 degrees.Angle of deviation is = 2* the glance angle so 2*60 = 120 degrees.Hence delta= 120 degrees.

answer;120 degrees.