Question

What is the degree of unsaturation of the compound formed by the reaction of formaldehyde with excess of ammonia?

Answer 1

Answer:

degree of unsaturation is 3

Explanation:

Answer 2

Answer:

The degree of unsaturation of the compound formed by the reaction of formaldehyde with an excess of ammonia is 3

Explanation:

The degree of unsaturation is equal to the total number of rings plus the total number of -bonds, as we all know.

If the molecular formula of a compound is given, the formula for the degree of unsaturation is written as follows:

$Degree of unsatuation =\frac{2C+2+N-X-H}{2}$

where C is the number of carbons

N is the number of nitrogen

X is the number of halogens(F, Cl, Br, or I)

H is the number of hydrogens

In this reaction, when formaldehyde is treated with excess ammonia hexamethylenetetramine is formed

$6CHO +4NH_3$            →            $(CH_2)_6N_4 +6H_2O$  

Formaldehyde + Ammonia   →  Hexamethylene tetramine + water

The molecular formula of hexamethylenetetramine is $C_6H_{12}N4$

So the degree of unsaturation = $\frac{2C+2+N-X-H}{2}$

Here the number of carbon is 6, the number of nitrogen is 4, the number of hydrogen is 12, and the number of halogens is 0.

While substituting this  in the above equation

$Degree of unsaturation =\frac{(2*6)+2+4-0-12}{2}$

$Degree of unsaturation = \frac{12+2+4-12}{2}$

                                     =3