Question

What is the density of a 700 kg object with a volume of 649 m3? (Density: D = D = m over v.)

Answer 1

Answer:

1.07 kg/m^3

Explanation:

m=700kg

v=649m3

d=700/649=1.07

Answer 2

The density is $D= 1.08 \frac{kg}{m^{3}}$.

Explanation:

The formula for the density is as follows as;

$D = \frac{m}{V}$

Here, D is the density, m is the mass and V is the volume.

Density is inversely proportional to the volume and it is directly proportional to the mass.

It is given in the problem that density of an object is 700 kg having volume $649 m^{3}$.

Put $m=649 m^{3}$ and V= 700 kg in the expression of density.

$D=\frac{700 kg}{649 m^{3}}$

$D= 1.08 \frac{kg}{m^{3}}$

Therefore, the density of an object is $D= 1.08 \frac{kg}{m^{3}}$.