What is the derivative of dy/dx=sinx^x+cosx^x
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dy/dx = sin^2x + cos^2x
dy/dx = 1
dy/dx = 0
Hope it helped you....
dy/dx = 1
dy/dx = 0
Hope it helped you....
vishvendave123:
No it's not sin^2x + cos^2x but
Sinx^x + cosx^x
let sinx^x = p , cosx^x = q and solve both by taking log both side and add them... you will get the answr...
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