what is the derivative of f(x)= -Sin^2x-Cos^2x
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by taking the minus sign common it would be sin²x+cos²x which is 1 then f(x)=(-1) and -1 is constant term hence the derivative will be 0
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a/x+b/y=a+b a/x^2+b/y^2=2
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so i have to find x and y?
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Simple way of doing this is :
f(x) = - sin^2 x - cos^2 x = - 1
f'(x) = 0 as -1 is a constant.
We can also find derivative of sin^2 x as 2 sinx cosx.
and that of cos^2 x as 2 cos x * (-sinx)
and then adding these two terms we get 0.
f(x) = - sin^2 x - cos^2 x = - 1
f'(x) = 0 as -1 is a constant.
We can also find derivative of sin^2 x as 2 sinx cosx.
and that of cos^2 x as 2 cos x * (-sinx)
and then adding these two terms we get 0.
:-)
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