Question

what is the derivative of log x and 1/tan X ???​

Answer 1

$\orange{\mathbb{DERIVATIVES}} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt \frac{d(logx)}{dx} = \frac{1}{x} }}}} \\ \\ \tt \frac{1}{tanx} = cotx \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt \frac{d(cotx)}{dx} = -{cosec}^{2}x }}}} \\ \\ \green{\frak {Some\:other\: derivatives}} \\ \\ \tt \circ \frac{d({x}^{n})}{dx} = n{x}^{n-1} \\ \\ \tt \circ \frac{d({e}^{x})}{dx} = {e}^{x} \\ \\ \tt \circ \frac{d(sinx)}{dx} = cosx \\ \\ \tt \circ \frac{d(cosx)}{dx} = - sinx \\ \\ \tt \circ \frac{d(tanx)}{dx} = {sec}^{2}x \\ \\ \tt \frac{d(cosec)}{dx} = -cosecx.cotx \\ \\ \tt \circ \frac{d(secx)}{dx} = secx.tanx$