Question

what is the derivative of sin^nx give the solution with full explanation​

Answer 1

Answer:

$\frac{d { \sin}^{n} x}{dx} = n \sin( {x}^{n - 1} ) \frac{d \sin(x) }{dx} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = n \sin( {x}^{? \: n - 1} ) \cos(x)$