Math, asked by harshi3283, 11 months ago

what is the derivative of sinx/cosx

Answers

Answered by manojkalwar3395
0
sinx
-------- =tanx
cosx
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this is your answer
Answered by Anonymous
0

Answer: - 1 / cos^2x


Step-by-step explanation:


[ Sinx d( cos x) /dx - cos x d ( sin x )/ dx] / ( cos x^2 )


=> [sinx ( - sinx ) - cos x ( cos x )] / cos^2x


=> ( - sin^2 x - cos^2 x ) / cos^2 x


=> - 1 ( sin^2 x + cos^2x ) / cos^2x


=> - 1 / cos^2 x

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