Question

what is the derivative of sinx/cosx

Answer 1

sinx
-------- =tanx
cosx
please mark me as a brainelist

this is your answer

Answer 2

Answer: - 1 / cos^2x

Step-by-step explanation:

[ Sinx d( cos x) /dx - cos x d ( sin x )/ dx] / ( cos x^2 )

=> [sinx ( - sinx ) - cos x ( cos x )] / cos^2x

=> ( - sin^2 x - cos^2 x ) / cos^2 x

=> - 1 ( sin^2 x + cos^2x ) / cos^2x

=> - 1 / cos^2 x