Math, asked by Matatagi8810, 11 months ago

What is the derivative of x^2-x+3 at the point x=5

Answers

Answered by harisurya0102
0

Answer:

Step-by-step explanation:

From given

=d/dx(x^2-x+3)

= 2x-1

X=1/2

From given the derivative of x^2-x+3 at x=5 is

=10-1

9

Answered by Sharad001
60

Question :-

What is the derivative of x² - x + 3 at the point

x = 5 .

Answer :-

 \to \boxed{ \sf \frac{dy}{dx} \bigg |_{x =  5}  \:  = 9} \:

Solution :-

We have and let ,

 \longmapsto \sf \:  y =  {x}^{2}  - x + 3 = 0 \\  \\ \sf differentiate \: with \: respect \: to \: x \\  \\  \to \sf \frac{dy}{dx}  =  \frac{d}{dx} {x}^{2}   -  \frac{d}{dx} x +  \frac{d}{dx}  3 \\  \\  \boxed{ \because \sf\frac{d}{dx}  {x}^{n}  = n {x}^{n - 1}  \: and \:  \frac{d}{dx}  \: constant = 0} \\  \\  \to \sf  \frac{dy}{dx}  = 2x - 1 + 0 \\ \bf hence \\  \\ \to \sf \frac{dy}{dx} \bigg |_{x =  5}  \:  = 2 \times 5- 1 \\  \\  \to \: \sf \frac{dy}{dx} \bigg |_{x =  5}  \:  = 10 - 1 \\  \\  \to \boxed{ \sf \frac{dy}{dx} \bigg |_{x =  5}  \:  = 9}

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