Question

What is the derivative of y = √x ??​

Answer 1

Answer:

$\frac{dy}{dx} = \frac{d \sqrt{x} }{dx} = \frac{1}{2 \sqrt{x} }$

Step-by-step explanation:

$y = \sqrt{x} = {x}^{ \frac{1}{2} } \\ \frac{dy}{dx} = \frac{d( {x}^{ \frac{1}{2} }) }{dx} \\ = \frac{1}{2} {x}^{ \frac{1}{2} - 1} \\ = \frac{1}{2} {x}^{ - \frac{1}{2} } \\ = \frac{1}{ {2x}^{ \frac{1}{2} } } \\ = \frac{1}{2 \sqrt{x} }$

Answer 2

welcome to the concept of the chain rule .

I hope it help you ✌️ ✌️