What is the derivatives x^3
By Using First Principle
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If y = x^n
Then dy/dx = nx^(n-1)
Here , y=x³ so n=3
dy/dx = 3x^(3-1) = 3x²
Then dy/dx = nx^(n-1)
Here , y=x³ so n=3
dy/dx = 3x^(3-1) = 3x²
suhailroushan:
By Using First Principle
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