Physics, asked by harijith03, 4 months ago

what is the diamension fournula of gravitational constant​

Answers

Answered by Anonymous
4

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Derivation. Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

Answered by Sanjanahere
6

Answer:

Derivation. Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

Explanation:

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