what is the diameter of a base of cone having slant height 41 cm and height is 40 cm
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We know that,
(Slant height) ^2 = (Height)^2 + (Base)^2
=> l^2 = h^2+b^2
=> (41)^2 = (40)^2 + b^2
=> 1681 = 1600 + b^2
=> 1681-1600 = b^2
=> b = root81
=> b = 9 cm
Be Brainly
(Slant height) ^2 = (Height)^2 + (Base)^2
=> l^2 = h^2+b^2
=> (41)^2 = (40)^2 + b^2
=> 1681 = 1600 + b^2
=> 1681-1600 = b^2
=> b = root81
=> b = 9 cm
Be Brainly
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