Question

what is the diameter of a circle whose area is equal to the sum of the area of two side circle of radii 40cm and 9 cm?​

Answer 1

Step-by-step explanation:

SOLUTION:-

The radius of the 1st circle is 40cm

the area of the circle is:πr^2=3.14×40×40=5024cm^2

The radius of the 2nd circle is 9cm

the area of the circle is:πr^2=3.14×9×9=254.34cm^2

As per the question,

The area of the 3rd circle i=the area of the 1st circle+ the area of the 2nd circle

=(5024+254.34)cm^2

=5278.34cm^2

the radius of the 3rd circle is:√(5278.34/3.14)=√1681=41cm

so the diameter is 2r=2×41=82cm

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