what is the diameter of a circle whose area is equal to the sum of the area of two side circle of radii 40cm and 9 cm?
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Step-by-step explanation:
SOLUTION:-
The radius of the 1st circle is 40cm
the area of the circle is:πr^2=3.14×40×40=5024cm^2
The radius of the 2nd circle is 9cm
the area of the circle is:πr^2=3.14×9×9=254.34cm^2
As per the question,
The area of the 3rd circle i=the area of the 1st circle+ the area of the 2nd circle
=(5024+254.34)cm^2
=5278.34cm^2
the radius of the 3rd circle is:√(5278.34/3.14)=√1681=41cm
so the diameter is 2r=2×41=82cm
mark as brainlist plz mate
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