Question

What Is The Diameter Of Shaft In Forced Apply 425KN And Compressive Strength Is 8.5N/mm Cube ?

Answer 1

Answer:

Step-by-step explanation:

To answer this question we must first interpret it correctly.

425kN = 425000N

The compressive strength is :

8.5N/mm cube

Let us get the total volume as follows :

8.5 N = 1mm cube

425000N =?

We get this by cross multiplication.

We have :

425000/8.5 × 1 = 50000 mm cube

The diameter is the cube root of this.

We have :

Cube root of 50000 = 36.84 mm

Answer :

36.84 mm