what is the diference when dy/dx = 0 and d 2 y/dx 2 = 0
Answers
Answered by
1
hey friend.
=) dy/dx is the 1st derivative of any function..
=) dy/dx represent the slope of tangent at any point
But d^2y/dx^2 is second derivative.
=)it represent curvature of any curve.
=) curvature in sense :-
where curve will turn I.e upward or downward.
example :--
let a function :- y = x^2
so dy/dx = 2x
=) slope if tangent at any point is " 2x "
and,..
=) d^2y/dx^2 = 2
but ,. 2 > 0 (positive ) so curve is open upward ....
if second derivative comes to be negative (<0 ) then curve open downward.
this is the geometrical meaning of second derivative.
______________________________
hope it will help u
=) dy/dx is the 1st derivative of any function..
=) dy/dx represent the slope of tangent at any point
But d^2y/dx^2 is second derivative.
=)it represent curvature of any curve.
=) curvature in sense :-
where curve will turn I.e upward or downward.
example :--
let a function :- y = x^2
so dy/dx = 2x
=) slope if tangent at any point is " 2x "
and,..
=) d^2y/dx^2 = 2
but ,. 2 > 0 (positive ) so curve is open upward ....
if second derivative comes to be negative (<0 ) then curve open downward.
this is the geometrical meaning of second derivative.
______________________________
hope it will help u
Similar questions
Science,
6 months ago
Physics,
6 months ago
Social Sciences,
1 year ago
Sociology,
1 year ago
English,
1 year ago