Question

what is the difference below the sum of first 20 terms ,next 20 terms (AP:6,10,14)​

Answer 1

Answer:

5621+3248=88691745470469

Answer 2

Answer:

Term 1 is 6.

The difference is 4.

Term 20 is 6 + 19 x 4 = 82.

Term 21 is 86.

Term 40 is 6 + 39 x 4 = 162.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.The sum of the next 20 terms is 20/2 (86 + 162) = 2480.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.The sum of the next 20 terms is 20/2 (86 + 162) = 2480.The difference of the sums is 2480 - 880 = 1600.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.The sum of the next 20 terms is 20/2 (86 + 162) = 2480.The difference of the sums is 2480 - 880 = 1600.Alternately the sum of all 40 terms is 40/2 (6 + 162) = 3360.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.The sum of the next 20 terms is 20/2 (86 + 162) = 2480.The difference of the sums is 2480 - 880 = 1600.Alternately the sum of all 40 terms is 40/2 (6 + 162) = 3360.The sum of the second 20 terms is 3360 - 880 = 2480.

Term 40 is 6 + 39 x 4 = 162.The sum of the first 20 terms is 20/2 (6 + 82) = 880.The sum of the next 20 terms is 20/2 (86 + 162) = 2480.The difference of the sums is 2480 - 880 = 1600.Alternately the sum of all 40 terms is 40/2 (6 + 162) = 3360.The sum of the second 20 terms is 3360 - 880 = 2480.The difference is still 2480 - 880 = 1600.