what is the difference between no. of moles and stoichiometric coefficient?
Answers
Explanation:
For starters, you know that you can think of a balanced chemical equation as using both moles and molecules.
For example, let's say that you have
2
molecules of hydrogen gas and
1
molecule of oxygen gas in the right conditions to produce a reaction.
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
l
)
So when the reaction takes place,
2
molecules of hydrogen gas react with
1
molecule of oxygen gas to produce
2
molecules of water.
This is true because a balanced chemical equation must make sense at a molecular level.
Now, you always need
6.022
⋅
10
23
particles of a substance in order to have
1
mole of that substance, as given by Avogadro's constant.
So if we use
N
A
to designate Avogadro's constant, or
6.022
⋅
10
23
particles per mole, you can say that
1 mole H
2
=
N
A
.
molecules H
2
1 mole O
2
=
N
A
.
molecules O
2
1 mole H
2
O
=
N
A
.
molecules H
2
O
This means that you can express the molecules that take part in the reaction in moles by going
2
molecules H
2
⋅
1 mole H
2
N
A
molecules H
2
=
(
2
N
A
)
.
moles H
2
1
molecule O
2
⋅
1 mole O
2
N
A
molecules O
2
=
(
1
N
A
)
.
moles O
2
2
molecules H
2
O
⋅
1 mole H
2
O
N
A
molecules H
2
O
=
(
2
N
A
)
.
moles H
2
O
If you rewrite the balanced chemical equation using moles instead of molecules, you will end up with
(
2
N
A
)
H
2
(
g
)
+
(
1
N
A
)
O
2
(
g
)
→
(
2
N
A
)
H
2
O
(
l
)
But since
N
A
is present in the denominator on all species that take part in the reaction, you can simplify it
(
2
N
A
)
H
2
(
g
)
+
(
1
N
A
)
O
2
(
g
)
→
(
2
N
A
)
H
2
O
(
l
)
and get
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
l
)
As you can see, the balanced chemical equation can be understood to refer to both molecules and moles, i.e. the mole ratio is equivalent to the molecule ratio.
So, for example, let's say that you start with
10
moles of hydrogen and excess oxygen gas and you want to find out how many molecules of water are produced.
The balanced chemical equation tells you that you get
2
moles of water for every
2
moles of hydrogen gas, so you will get
10
moles of water.
Since
1
mole of water contains
N
A
molecules of water, you can say that you will get
10
×
N
A
molecules of water.
Similarly, if you start with
10
molecules of hydrogen gas and excess oxygen, you will get
10
molecules of water, which is equivalent to
10
N
A
moles of water.