Math, asked by SaAwesome, 7 months ago

What is the difference between the circumference of the outer circle and the circumference of the inner circle? Leave your answer in terms of π.


A. 2π m
B. 4π m
C. 7π m
D. 18π m


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Answers

Answered by Anonymous
24

Given :

  • Radius of outer circle = 9 m.
  • Difference between the radius of the outer circle and radius of inner circle = 2 m.

To find :

  • Difference between the circumference of the outer circle and the circumference of inner circle.

Solution :

Formula Used :-

{\boxed{\bold{Circumference\:of\: circle=2\pi\:r}}}

In case of outer circle,

  • Radius = 9 m

Circumference of outer circle,

= 2πr

= (2π × 9) m

= 18π m

In case of inner circle ,

  • Difference between the radius of the outer circle and radius of inner circle = 2 m.

Then,

Radius of inner circle = (9-2) m = 7 m

Circumference of inner circle ,

= 2πr

= (2π × 7) m

= 14π m

So, the difference between their circumference,

= (18π - 14π) m

= m

Therefore, the difference between the circumference of the outer circle and the circumference of inner circle is 4π m.

{\boxed{\sf{Option\:(B)\:is\: the\: correct\:answer}}}

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Answered by sethrollins13
10

✯✯ QUESTION ✯✯

What is the difference between the circumference of the outer circle and the circumference of the inner circle? Leave your answer in terms of π.

A. 2π m

B. 4π m

C. 7π m

D. 18π m

━━━━━━━━━━━━━━━━━━━━

✰✰ ANSWER ✰✰

Using Formula : -

\longrightarrow{\small{\boxed{\boxed{\bold{\purple{\sf{Circumference\:of\:Circle=2πr}}}}}}}

For Outer Circle : -

\longrightarrow{Radius=9m}

Now ,

\longrightarrow{Outer\:Circle=2πr}

\longrightarrow{2π(9)}

\longrightarrow{18πm}

As Given that difference between Radius of Outer and Inner Circle is 2m. So,

\longrightarrow{Radius(Inner\:Circle)=9-2=7m}

For Inner Circle : -

\longrightarrow{Inner\:Circle=2πr}

\longrightarrow{2π(7)}

\longrightarrow{14πm}

Difference between their circumference is : -

\longrightarrow{Outer\:Circumference-Inner\:Circumference}

\longrightarrow{18π-14π}

\longrightarrow{4πm}

So,Option B) is Correct .....

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