Math, asked by SaAwesome, 10 months ago

What is the difference between the circumference of the outer circle and the circumference of the inner circle? Leave your answer in terms of π.


A. 2π m
B. 4π m
C. 7π m
D. 18π m


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Answers

Answered by Anonymous
24

Given :

  • Radius of outer circle = 9 m.
  • Difference between the radius of the outer circle and radius of inner circle = 2 m.

To find :

  • Difference between the circumference of the outer circle and the circumference of inner circle.

Solution :

Formula Used :-

{\boxed{\bold{Circumference\:of\: circle=2\pi\:r}}}

In case of outer circle,

  • Radius = 9 m

Circumference of outer circle,

= 2πr

= (2π × 9) m

= 18π m

In case of inner circle ,

  • Difference between the radius of the outer circle and radius of inner circle = 2 m.

Then,

Radius of inner circle = (9-2) m = 7 m

Circumference of inner circle ,

= 2πr

= (2π × 7) m

= 14π m

So, the difference between their circumference,

= (18π - 14π) m

= m

Therefore, the difference between the circumference of the outer circle and the circumference of inner circle is 4π m.

{\boxed{\sf{Option\:(B)\:is\: the\: correct\:answer}}}

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Answered by sethrollins13
10

✯✯ QUESTION ✯✯

What is the difference between the circumference of the outer circle and the circumference of the inner circle? Leave your answer in terms of π.

A. 2π m

B. 4π m

C. 7π m

D. 18π m

━━━━━━━━━━━━━━━━━━━━

✰✰ ANSWER ✰✰

Using Formula : -

\longrightarrow{\small{\boxed{\boxed{\bold{\purple{\sf{Circumference\:of\:Circle=2πr}}}}}}}

For Outer Circle : -

\longrightarrow{Radius=9m}

Now ,

\longrightarrow{Outer\:Circle=2πr}

\longrightarrow{2π(9)}

\longrightarrow{18πm}

As Given that difference between Radius of Outer and Inner Circle is 2m. So,

\longrightarrow{Radius(Inner\:Circle)=9-2=7m}

For Inner Circle : -

\longrightarrow{Inner\:Circle=2πr}

\longrightarrow{2π(7)}

\longrightarrow{14πm}

Difference between their circumference is : -

\longrightarrow{Outer\:Circumference-Inner\:Circumference}

\longrightarrow{18π-14π}

\longrightarrow{4πm}

So,Option B) is Correct .....

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