Math, asked by Annamr307, 10 months ago

What is the difference between the compound interest, when interest is compounded 5-monthly,
and the simple interest on a sum of ₹12,000 for 1 years at 12% per annum?

Answers

Answered by aniruddha2585
8

Step-by-step explanation:

we have to use the formula p{1+R/100}

Answered by slicergiza
3

Difference would be rs 50.73 ( approx )

Step-by-step explanation:

Since, the compound interest formula is,

I=P(1+r)^{t}-P

Simple interest formula,

I=P\times r\times t

Where,

P = principal,

r = rate of interest per period,

t = number of periods,

If P = 12000, annual rate = 12% = 0.12 ⇒ rate per 5 month = \frac{0.12\times 5}{12}=0.05,

Number of periods, t = 12/5 ( 1 year = 12 months )

Thus, compound interest,

I_1=12000(1+0.05)^\frac{12}{5}-12000

=12000(1.05)^\frac{12}{5}-12000

\approx 1490.73 ( using calculator ),

If P = 12000, r = 12% = 0.12, t = 1 year,

Simple interest,

I_2=12000\times 0.12\times 1=1440

Hence, the difference in interests,

I_1-I_2=1490.73-1440=50.73\text{ rupees}

#Learn more:

Difference between compound interest and simple interest :

https://brainly.in/question/950403

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