Question

what is the difference between the place values of the two 7's in seventy thousand seven hundred ? ​

Answer 1

Step-by-step explanation:

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Complete step-by-step answer:

First, we will find the place values of the two sevens.

The first digit from the right is the digit on the unit’s place.

The second digit from the right is the digit on the ten’s place.

The third digit from the right is the digit on the hundred’s place.

The fourth digit from the right is the digit on the thousand’s place.

The fifth digit from the right is the digit on the ten thousand’s place.

Now, the first seven in the number 70674 is the second digit from the right.

Therefore, the first 7 is at the ten’s place.

The place value of a digit is the value of the digit.

Thus, we get the place value of 7 at the ten’s place as 7×10=70

.

Next, the next seven in the number 70674 is the fifth digit from the right.

Therefore, the first 7 are at the ten thousand’s place.

Thus, we get the place value of 7 at the ten thousand’s place as 7×10000=70000

.

Finally, we will find the difference in the place values of the two sevens.

Subtracting 70 from 70000, we get

Difference in place values of the two 7’s in 70674 =70000−70

Subtracting the terms, we get

Difference in place values of the two 7’s in 70674 =69930

Therefore, we get the difference between the place value of the two sevens in the number 70674 as 69,930.

Note: We have found the place values of the two 7’s in the number 70674. The number 70674 can be written as the sum of the place values of the 5 digits in the number.

Rewriting the number 70674, we get

70674=70000+600+70+4

Rewriting the terms, we get

70674=7×10000+6×100+7×10+4

Thus, we have expressed 70674 as the sum of place values, given by 7×10000

, 6×100

, 7×10

, and 4.