Chemistry, asked by siddharth5571, 6 months ago

What is the difference in chemical properties of propanal and propanone?​

Answers

Answered by Waniiqra1234
0

Answer:

(i) Propanone gives iodoform test while propanol does not give this test.

Propanone

CH

3

COCH

+3I

2

+2Na

2

CO

3

Yellowppt

CHI

3

+CH

3

COONa+2NaI+2CO

2

+H

2

O

(ii) Benzaldehyde (C

6

H

5

CHO) and acetophenone (C

6

H

5

COCH

3

) can be distinguished by iodoform test.

Acetophenone, being a methyl ketone on treatment with I

2

/NaOH undergoes iodoform reaction to give a yellow ppt. of iodoform. on the other hand, benzaldehyde does not give this test.

C

6

H

5

COCH

3

+3NaOI

Acetophenone

C

6

H

5

COONa+

Iodoform

CHI

3

+2NaOH

C

6

H

5

CHO

NaOI

No yellow ppt of iodoform

Benzaldehyde

(b)

(i) Methyl ter-butyl ketone < Acetone < Acetaldehyde

When HCN reacts with a compound, the attacking species is a nucleophile, CN

.

Therefore, as the negative charge on the compound increases, its reactivity with HCN decreases. In the given compounds, the +I effect increases as shown below. It can be observed the steric hindrance also increase in the same.

(ii) 4-Methoxybenzoic acid < Benzoic acid < 3, 4-Dinitrobenzoic acid

Electron-donating group decrease the strengths of acids, while electron-withdrawing groups increases the strengths of acids. As methoxy group is an electron-donating group, 4-ethoxybenzoic acid is a weaker acid than benzoic acid. Nitro group is an electron-withdrawing group and will increase the strengths of acids.

(iii) (CH

3

)

2

CHCOOH<CH

3

CH(Br)CH

2

COOH<CH

3

CH

2

CH(Br)COOH

After losing a proton, carboxylic acids gain a negative charge as shown:

R−COOH→R−COO

+H

+

Now, any group that will help stabilise the negative charge will increase the stability of the carboxyl ion and as a result, will increase the strength of the acid. Thus, groups having +I effect will decrease the strength of the acids and groups having -I effect will increase the strength of the acids. In the given compounds, −CH

3

group has +I effect and Br

group has −I effect. Thus, acid containing Br

are stronger.

The −I effect grows weaker as distance increase. Hence, CH

3

CH(Br)CH

2

COOH is weaker acid than CH

3

CH

2

CH(Br)COOH.

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