Math, asked by veronicamcrae1738, 1 year ago

What is the difference of the polynomials?

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5

Answers

Answered by somi173
0

Answer:

"  -2 x³ y² + 9 x² y³ - 3 x y⁴ - 6 x⁴ y + y⁵  "  is required difference of the given polynomials

Step-by-step explanation:

The given polynomial are

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

We can write these clearly

( -2 x³ y² + 4 x² y³ - 3 x y⁴ ) - ( 6 x⁴ y - 5 x² y³ - y⁵ )

While opening the brackets, the sign of the values in the second bracket will be changes. So we have

=  -2 x³ y² + 4 x² y³ - 3 x y⁴  -  6 x⁴ y + 5 x² y³ + y⁵

= -2 x³ y² + 4 x² y³ + 5 x² y³ - 3 x y⁴ - 6 x⁴ y + y⁵

= -2 x³ y² + 9 x² y³ - 3 x y⁴ - 6 x⁴ y + y⁵

It is required difference of the given polynomials

I hope it will help you.

Answered by MaheswariS
0

Answer:


Step-by-step explanation:

(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^5)

=-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4}-6x^{4}y+5x^{2}y^{3}+y^5

=-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^5

I hope this answer helps you


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