Question

what is the differentiation of cos³x ?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

-3cos²x sinx

here,

dcos³x/dx

= $\frac{dcos^3 x}{dcos x}$×$\frac{dcosx}{dx}$

=3cos²$x$ × (-sin$x$)

-3cos²$x$ sin$x$