Question

what is the differentiation of log2x​

Answer 1

Answer:

d/dx(log2x)=1/x

Explanation:

d/dx(logx)=1/x

here

d/dx(log2x)=1/2x *d/dx(2x)

=1/2x*2

=1/x

Answer 2

The differentiation of log2x is 1/x.

Given,

log2x is given.

To find,

Differentiation of log2x.

Solution,

Differentiation is a process of finding the derivative of a function.

We have to follow certain rules for differentiation.

Like, the Differentiation of any constant value is always 0.

The differentiation of logx is 1/x.

The differentiation of x concerning x is 1.

Let,

The function y=log2x....... equation (i).

We have to find the differentiation of log2x.

We know the differential of logx is equal to 1/x.

So,

Differentiating both sides of equation (i) with respect to x.

We get,

$\frac{dy}{dx}$=$\frac{d}{dy}$(log2x)

or,$\frac{dy}{dx}$= $\frac{1}{2x}$×2

or,$\frac{dy}{dx}$=$\frac{1}{x}$

So, the differentiation of log2x with respect to x is 1/x.

The differentiation of log2x is 1/x.

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