Question

what is the differentiation of xlogx​

Answer 1

Answer:

1+logx

is the right answer..

Answer 2

Answer:

$\frac{d}{dx} x log(x) = x \frac{d}{dx} log(x) + log(x) \frac{dx}{dx} \\ = x \times \frac{1}{x} + log(x) \\ = log(x) + 1$