Question

what is the dimensiomal formula of apsilen note

Answer 1

According to Coulomb's Law:

F=(1/4πε₀)q1q2/r²

ε₀=(1/4πF) q1q2/r²

Dimension formula of F=M¹L¹T⁻²

Charge =q=IXT=AxT¹ where A= electric current  

ε₀=(1/M¹L¹T⁻²)(AT¹xAT¹)/L²

ε₀=M⁻¹L⁻³T⁴A²

∴ Dimensional Formula of Epsilon not= M⁻¹L⁻³T⁴A²

Answer 2

According to Coulomb's Law:

F=(1/4πε₀)q1q2/r²

ε₀=(1/4πF) q1q2/r²

Dimension formula of F=M¹L¹T²

Charge =q=IXT=AxT¹ where A= electric current

ε₀=(1/M¹L¹T²)(AT¹xAT¹)/L²

ε₀=M¹L³T⁴A²

∴ Dimensional Formula of Epsilon not= M¹L³T⁴A²