what is the dimension (2D/3D)of magnetic flux density?
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Answer:
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Answered by
0
Answer:
Correct option is
B
[M
1
L
2
T
−2
A
−1
]
The force experienced by a moving charge in a magnetic field is given by F=q(
v
×
B
)
Here,
B
is the magnetic field or magnetic flux density or magnetic flux per unit area.
Thus, dimensions of magnetic flux [Φ]=[B]×[Area]=
[q][v]
[F][A]
We know the dimensions of the following as-
[F]=[M
1
L
1
T
−2
]
[A]=[L
2
]
[q]=[A
1
T
1
]
[v]=[L
1
T
−1
]
Thus, [Φ]=
[A
1
T
1
][L
1
T
−1
]
[M
1
L
1
T
−2
][L
2
]
=[M
1
L
2
T
−2
A
−1
]
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