What is the dimension formula of young's modulus
Answers
Answered by
136
Young's modulus = Stress/Strain
= F/A x e/l
= ma/A x e/l
Where,
F = force
A = area of cross section
e = elongation
l = actual length
a = acceleration
m = mass
By their units,
Y = [(kg x m/s²) / (m²)] x m/m
Y = (Kg x m) / (m²s²)
Y = Kg/ms²
In dimension formula Y = [ M L⁻¹ S⁻²]
= F/A x e/l
= ma/A x e/l
Where,
F = force
A = area of cross section
e = elongation
l = actual length
a = acceleration
m = mass
By their units,
Y = [(kg x m/s²) / (m²)] x m/m
Y = (Kg x m) / (m²s²)
Y = Kg/ms²
In dimension formula Y = [ M L⁻¹ S⁻²]
Answered by
53
Youngs modulus= strain/strain
=F/A*e/l
=[MLT^-2]/[L]^2 *
[L]/[L]
=[ML^-1 T^-2 ]
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