Question

what is the dimensional formula for electric field

Answer 1

according to me its L 3is up MT−3is up I−1. hope it helps.
please mark it brainliest.

Answer 2

Answer:

The dimensional formula for electric field is $\bold{\mathrm{M}^{1} \mathrm{L}^{1} \mathrm{A}^{-1} \mathrm{T}^{-3}}$

Explanation:

Force on a point charge is given by Coulomb’s Law. Coulomb’s Law gives magnitude of force(F) between two point charges q1  and q2 separate by distance r.

$\mathrm{F}=\frac{\mathrm{K}|\mathrm{q} 1 \mathrm{q} 2|}{r^{2}} \rightarrow(1)$

Where, $K=\frac{1}{4 \pi \epsilon_{0}}$

Here, Unit of force = Newton & unit of $\epsilon_{0}=C^{2} \times \frac{m^{2}}{N}$

Electric field (E) is field produced by a charge Q around its surroundings.  

Say a point test charge q is placed at distance r from Q. Then $E =KQ/r^2$   --- (2)

From (1) & (2), we can observe that,  

E = F/q = m x a / I x t  

= Newton / Coulomb = Kg x m / Amp x $\mathrm{Sec}^{3}$  

$=\mathrm{M}^{1} \mathrm{L}^{1} / \mathrm{A} \mathrm{T}^{3}$

Hence dimensional formula for electric field is $\bold{\mathrm{M}^{1} \mathrm{L}^{1} \mathrm{A}^{-1} \mathrm{T}^{-3}}$