what is the dimensions of a/b in the relation F=ax+bt.
Answers
Answered by
6
f = a√x + bt2, where [f] = [M L T −2], [x] = [L] and [t] = [T].
LHS is force. So both the terms on the RHS have the dimensions of force.
[f] = [a√x] = [bt2]
[f] = [a√x]
[M L T −2] = [a L½]
⇒ [a] = [M L½ T −2]
[f] = [bt2]
[M L T −2] = [b T2]
⇒ [b] = [M L T−4]
[a]/[b] = [M L½ T −2]/[M L T−4] = [M0 L−½ T2]
Therefore [a/b] = [M0 L−½ T2]
hope it is helpfull to you..
so please follow me
Similar questions