Question

what is the dimensions of a rectangle whose perimeter is 24 units and whose area is 35 units square

Answer 1

$2(x + y) = 24 \\ xy = 35 \\ y = 35 \div x \\ 2x + 2 \times 35 \div x = 24 \\ 4 {x}^{2} + 70 = 24x \\ 4 {x}^{2} - 24x + 70 = 0 \\ \\ x = 5and7 \div 2 \\ sub x iny \\ y = 7and10$