Question

What is the dimensions of self inductance?

Answer 1

Answer:

It unit of self induction is henry (H) and its dimensional formula is [ML2T -2A-2]. A = area of cross-section of the coil. The phenomena of production of induced emf in a circuit due to the change in magnetic flux in itsneighbouring circuit, is called mutualinduction.

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Answer 2

● Answer -

[L] = [L^2M1T-2A-2]

◆ Explanation -

Coefficient of self induction is given by -

L = V / (di/dt)

L = V.dt/di

In dimensional form,

[L] = [V][dt]/[di]

We know that _

[V] = [L2M1T−3A−1]

[dt] = [T]

[di] = [A]

Substitute this,

[L] = [L2M1T−3A−1][T]/[A]

[L] = [L^2M1T-2A-2]

Hence, dimensions of coefficient of self induction is [L^2M1T-2A-2].

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