Question

what is the discriminant of (x-2)^2=0?​

Answer 1

ANSWER: Zero

Step-by-step explanation:

(x-2)²= x²+2²-2(x)(2)

=x²+4-4x

=x²-4x+4

Here ; a=1 , b= -4 and c=4

Discriminant = b²-4ac

So,

Discriminant (D) = (-4)²-4(1)(4)

= 16-16

=0

Therefore the discriminant value is 0 .

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Answer 2

discriminant value is zero ( 0 )

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