what is the displacement of the point of a wheel initially in contact with the ground when the wheel rolls forward a revolution? take the radius of the wheel as R and the x-axis as the forward direction? along with steps
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let your point be on origin if after half revolution it is somewhere on the line y=2r considering your wheel is rigid every point on it will travel equal displacementtherefore leftmost point(on line y=r) will also travel distance 2rnow imagine it as one circle with x axis as a tangent to it at origin and another circle with x axis as a tangent to it at x=2r.It may be clear that those two circles will coincide at one point which is (r,r).this imagination will be like a initial photo before and after rotation which are merged together(maybe by photoshop)your point after rotation will be at (2r,2r) so by simple pythagores theorem you may get displacement 2r*21/2 or2r* root(2) please mark as brainliest
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kanna4:
along with steps please
Answered by
8
Given,
The radius of the wheel = R unit
X axis as the forward direction.
To find,
The displacement of the mentioned point.
Solution,
Due to one single revolution,the point which is in contact with the ground will travel a distance of the length of the perimeter of that wheel,in the forward x axis direction.
So,the displacement of the point
= 2×π×R = 2πR units
Hence,the displacement of the point will be 2πR units in the forward x axis direction.
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