Physics, asked by kanna4, 1 year ago

what is the displacement of the point of a wheel initially in contact with the ground when the wheel rolls forward a revolution? take the radius of the wheel as R and the x-axis as the forward direction? along with steps

Answers

Answered by jibysunny123
18
 let your point be on origin if after half revolution it is somewhere on the line y=2r considering your wheel is rigid every point on it will travel equal displacementtherefore leftmost point(on line y=r) will also travel distance 2rnow imagine it as one circle with x axis as a tangent to it at origin and another circle with x axis as a tangent to it at x=2r.It may be clear that those two circles will coincide at one point which is (r,r).this imagination will be like a initial photo before and after rotation which are merged together(maybe by photoshop)your point after rotation will be at (2r,2r) so by simple pythagores theorem you may get displacement 2r*21/2 or2r* root(2) please mark as brainliest

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kanna4: along with steps please
jibysunny123: ok
Answered by Anonymous
8

Given,

The radius of the wheel = R unit

X axis as the forward direction.

To find,

The displacement of the mentioned point.

Solution,

Due to one single revolution,the point which is in contact with the ground will travel a distance of the length of the perimeter of that wheel,in the forward x axis direction.

So,the displacement of the point

= 2×π×R = 2πR units

Hence,the displacement of the point will be 2πR units in the forward x axis direction.

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