what is the distance between (0,5)(7,0)
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Distacs between given points is sqrt 74
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HAI,
The distance between (0,5)(7,0) is
√(x2-x1)²+(y2-y1)²
√(7-0)²+(0-5)²
√(7)²+(5)²
√(49+25)
√(74)
therefore the distance between (0,5)(7,0) is √(74)cm
hope helped
The distance between (0,5)(7,0) is
√(x2-x1)²+(y2-y1)²
√(7-0)²+(0-5)²
√(7)²+(5)²
√(49+25)
√(74)
therefore the distance between (0,5)(7,0) is √(74)cm
hope helped
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