What is the distance between (0,-sin
x) and (-Cosx, 0)
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Distance between two points is √[(x2-x1)^2+(y2-y1)^2]
=√[(-cosx-0)^2+(0-(-sinx))^2]
=√[-cosx^2+sinx^2]
=✓[cosx^2+sinx^2] ... Sign is irrelevant as it is square number
=✓1=1
As cosx^2+sinx^2=1 (identity)
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