Question

What is the distance between (–2 and one-half, –3) and (1, –3)?

Answer 1

Answer:

use distance formula

a b is equal to under root of x 2 - X 1 whole square plus y2 to minus y 1 whole square

Answer 2

Recall the formula for finding distance in Coordinate Geometry:

$\text {Distance} = \sqrt{(Y_{2} -Y_{1})^2 +(X_{2} -X_{1})^2}$

Given:

The two points are $\bigg(-2\dfrac{1}{2} , -3\bigg)$ and $\bigg(1, -3\bigg)$

Find the distance between the two points:

$\text {Distance} = \sqrt{(Y_{2} -Y_{1})^2 +(X_{2} -X_{1})^2}$

$\text {Distance} = \sqrt{(-3 - (-3))^2 +(1 - (-2\frac{1}{2} )^2}$

$\text {Distance} = \sqrt{(-3 + 3)^2 +(1 + 2\frac{1}{2} )^2}$

$\text {Distance} = \sqrt{(0)^2 +(3\frac{1}{2} )^2}$

$\text {Distance} = \sqrt{(3\frac{1}{2} )^2}$

$\text {Distance} = 3\dfrac{1}{2} \text { units}$

Answer: The distance between these 2 points is 3 1/2 units.