What is the distance between (–5, –2) and (–5, –8)? On a coordinate plane, points are at (negative 5, negative 2) and (negative 5, negative 8). –10 units –6 units 6 units 10 units
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Answer: 6 units
Step-by-step explanation:
You can apply distance formula here.
Distance between the points = √(x2-x1)²+(y2-y1)²
here, x1 = -5 ; y1= -2 ; x2=-5 ; y2= -8
=> √ (-5-(-5))²+(-8-(-2))²
= √ (-5+5)²+(-8+2)²
= √ 0² + (-6)²
= √ 36
= 6 units.
Hope this will help you.
9229984:
thanks it was the right answer
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