Question

What is the distance between A on the x-axis whose abscissa is11 and B(7,3)

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Heya!!
The point A is on the x axis, so the y- coordinate of A would be 0., and tha abscissa is 11, so the coordinate becomes (11,0) .
The coordinate of B is given as (7,3).
Now the distance between these two points are to be measured.
$\sqrt{(x 1 - x2)^{2} + (y1 - y2)^{2}}$
this is the formula for finding the distance between any two given coordinates in a given plane.
Thus, by putting the given coordinates...we get
$\sqrt{(11 - 7)^{2} + {(0 - 3)}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ = 5$