Question

What is the distance between parallel lines whose equations are y=-x+2 and y=-x+8?

Answer 1

given lines y=x+2 and y=-×+8

x+y+2=0 , x+y-8=0

therefore compare with a1x+b1y+c1=0 and

a2x+b2y+c2=0

a1=1, b1=1, c1=2

a2=1, b2=1 , c2= -8

therefore, distance between parallel lines

$= |c1 - c2| \div \sqrt{ {a}^{2} { + b}^{2} }$

$= |2 + 8| \div \sqrt{1 + 1} \\ = |10| \div \sqrt{2} \\ = \sqrt{50}$

this is the method to solve the distance between parallel lines ...

hope this will helps you