What is the distance between the centre's of the largest and the smallest circle that are drawn touching all the the sides of the equilateral triangle of side 30cm?
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Answered by
1
Answer:
Given circle is (x−2)
2
+y
2
=4
Centre is (2,0) and radius =2
Therefore, distance between (2,0) and (5,6) is
9+36
=3
5
⇒r
1
=
2
3
5
−2
and r
2
=
2
3
5
+2
Then, r
1
r
2
=
4
41
Answered by
0
Step-by-step explanation:
to @vaibhavdhankhar
hey !!
well, first you have to correct your English
that was much
not your mucha
lol
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