What is the distance between the centre's of the largest and the smallest circle that are drawn touching all the the sides of the equilateral triangle of side 30cm?
Answers
Answered by
1
Answer:
Given circle is (x−2)
2
+y
2
=4
Centre is (2,0) and radius =2
Therefore, distance between (2,0) and (5,6) is
9+36
=3
5
⇒r
1
=
2
3
5
−2
and r
2
=
2
3
5
+2
Then, r
1
r
2
=
4
41
Answered by
0
Step-by-step explanation:
to @vaibhavdhankhar
hey !!
well, first you have to correct your English
that was much
not your mucha
lol
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