what is the distance between the point (10 cos 35° ,0) and (0, 10 cos 60°)
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let one coordinate be A(10cos30,0) and B(0,10cos60)
=>√(0-10cos30)^2+(10cos60-0)^2
=>100cos^2 30°+100cos^2 60°
=)100*[√3/2]^2+100(1/2)^2
=>25*3+25
=>100
=>√(0-10cos30)^2+(10cos60-0)^2
=>100cos^2 30°+100cos^2 60°
=)100*[√3/2]^2+100(1/2)^2
=>25*3+25
=>100
Answered by
27
100
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