Question

What is the distance between the points (–1, –1) and (4, –5)?

Answer 1

Step-by-step explanation:

When we know the horizontal and vertical distances between two points we can calculate the straight ... Now we can solve for c (the distance between the points): ... [ 52 + (−3)2 + (−1)2 ].

Answer 2

Answer:

Given :

The two points are : (–1, –1) and (4, –5)

To find :

Distance = ?

Formula :

The Distance between two points =

$\sqrt{( x_2 - x_1) ^{2} + (y_2 -y _1) ^{2}}$

Solution:

$\sqrt{(4 - ( - 1)) ^{2} + (( - 5) - ( - 1)) {}^{2}}$

$= \sqrt{(5) {}^{2} + ( - 4) {}^{2} }$

$= 25 + 16$

$= \sqrt{41}$

Therefore, the distance between the points (–1, –1) and (4, –5) is $\sqrt{41}$

Few other things related to this:

• The coordinates of any point on x-axis is (x, 0).

• The coordinates of any point on y-axis is (0,y).

• Midpoint formula :

$( \frac{x_1 + x_2} {2} , \frac{y_1 + y_2} {2} )$

• Centroid formula :

$( \frac{x_1 + x_2 + x_3} {3} , \frac{y_1 + y_2 + y_3} {3} )$