Question

what is the distance between thepoints A (sintita-costita,0) B(0,sintita +costita)?​

Answer 1

Theta is written as A.

Answer:

Distance between ( sinA - cosA, 0 ) and ( 0 , sinA + cosA ) is √2.

Step-by-step explanation:

Using distance formula :

• Distance between any two points A( a,b ) and B( c, d ) is given by √{ ( a - c )^2 + ( b - d )^2 } .

On the basis of this :

= > Distance between the given points

= > √{ ( sinA - cosA -0 )^2 + ( 0 - sinA - cosA ) }

= > √{ sinA - cosA )^2 + ( - sinA - cosA )^2 }

= > √{ sin^2 A + cos^2 A - 2sinAcosA + sin^2 A + cos^2 A + 2sinAcosA }

= > √{ 2( sin^2 A + cos^2 A ) }

= > √2( 1 )

= > √2

Hence distance between ( sinA - cosA, 0 ) and ( 0 , sinA + cosA ) is √2.

Answer 2

Answer:$\sqrt{2}$ is the answer

Step-by-step explanation: